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Solid State Chemistry and its Applications. Anthony R. WestЧитать онлайн книгу.

Solid State Chemistry and its Applications - Anthony R. West


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represents the 2‐fold rotation axis perpendicular to the plane of the circle and which passes through the centre of the sphere that the projection represents. The thin vertical line is a construction line; its significance can be seen in the companion drawing, (a) which shows the equivalent positions generated by the 2‐fold rotational symmetry. We know that, if an object possesses a 2‐fold rotation axis, it can be rotated by 180º about that axis to arrive at a position that is indistinguishable from the original position. This indistinguishable position or identical orientation is known, crystallographically, as an equivalent position and therefore, we can say that a 2‐fold rotation axis generates two equivalent positions. In (a), if our original position is shown as the small dot symbol, 1, that is above the plane of the stereographic projection, the 2‐fold axis generates an equivalent position at 2 which is also above the plane. On continuing with the rotation operation by a further 180º, position 2 moves around the circle to arrive back at starting position 1; hence, 1 and 2 are the two equivalent positions in this point group.

Schematic illustration of the point groups (a, b) 2, (c, d) 3, and (e–h) m.

       Figure 1.53 The point groups (a, b) 2, (c, d) 3, and (e–h) m.

Schematic illustration of the point groups (a) 1 negative and (b, c) 3 negative.

      Figure 1.54 The point groups (a)

and (b, c)
.

      Monoclinic point group m is shown in Fig. 1.53(e, f) and in another orientation in (g, h). This has a single mirror plane which lies in the plane of the projection in (f) and is represented as a thick circle. Equivalent positions are generated by reflection across the mirror plane and hence, our starting position 1, above the plane generates an equivalent position 2, represented by an open circle, directly underneath the plane (e). In (h) the same point group, m, is shown but oriented vertically and perpendicular to the plane of the circle. It is represented by the thick line that bisects the projection that is shown; in this orientation, the equivalent positions are either side of the mirror and both are shown above the plane, (g); equally, they could both be below the plane.

      The centre of symmetry in the point group, ModifyingAbove 1 With bar is shown in Fig. 1.54(a). It does not have a symbolic representation and hence, only one diagram showing the equivalent positions is given. Recall that a centre of symmetry represents two identical positions that are equidistant from the centre of an object and lie on a straight line passing through its centre. This generates the two equivalent positions shown in (a): 1 lies above the plane; 2 lies on a straight line that passes through the centre, to an equal distance the other side and therefore, is below the plane.

      The inversion axes, spoken as: bar n , i.e. ModifyingAbove 2 With bar, ModifyingAbove 3 With bar, ModifyingAbove 4 With bar and ModifyingAbove 6 With bar are combined symmetry operations involving the rotation component, and inversion through the centre, as in ModifyingAbove 1 With bar. The trigonal point group ModifyingAbove 3 With bar is shown in Fig. 1.54(b, c). The symbol for ModifyingAbove 3 With bar, in (c), is a solid triangle with an open circular centre. Six equivalent positions (b) are generated, 1–6, before finally returning to starting position 1. Point groups ModifyingAbove 2 With bar, ModifyingAbove 4 With bar and ModifyingAbove 6 With bar are shown in Appendix E; readers may like to confirm for themselves that point group ModifyingAbove 2 With bar is equivalent to a mirror plane perpendicular to the 2‐fold inversion axis.

      So far, we have considered point groups that have a single symmetry element. The three orthorhombic point groups shown in Fig. 1.55 all have combinations of symmetry elements. For each, again, two diagrams are used. First, point group 222 has the three, mutually perpendicular twofold axes shown in (b): one is perpendicular to the plane of the projection, passes through the centre and is represented by the lens‐shaped symbol in the centre of the projection; one runs vertically in the plane of the projection and is represented by two symbols on the circumference of the circle at the top and bottom; one runs horizontally in the plane of the projection and is represented by the two symbols at the left and right on the circle circumference.

Schematic illustration of the three orthorhombic point groups 222, mm2, and mmm.

       Figure 1.55 The three orthorhombic point groups 222, mm2, and mmm.

      In this case, however, no new equivalent positions are generated in (d). The third 2‐fold axis, shown vertically in the plane of the paper, is essentially redundant since it arises automatically from the presence of the other 2‐fold axes. The point group 222 could therefore be represented in the shortest possible notation as 22 because the third twofold axis is not independent. The longer notation is used in order to show consistency with the essential symmetry requirements (Table 1.1) for orthorhombic unit cells. The order in which the symmetry axes are considered in Fig. 1.56 is unimportant and any two of the 2‐fold axes together generate the third axis automatically.

      Orthorhombic point group mm2, Fig. 1.55 contains two mirror planes at right angles to each other with a 2‐fold axis passing along the line of intersection of the mirror planes (d). The 2‐fold axis is perpendicular to the paper and the mirror planes are indicated in projection as the thick lines lying horizontally and vertically. This point group also has four equivalent positions, but all are at the same height relative to the plane of the paper (c). As in the previous example, the third symmetry element


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