Basic Math & Pre-Algebra All-in-One For Dummies (+ Chapter Quizzes Online). Mark ZegarelliЧитать онлайн книгу.
$4, the result is not the same as if you have $4 and spend $6. In the first case, you still have $2 left over. In the second case, you owe $2. In other words, switching the numbers turns the result into a negative number. (I discuss negative numbers in Chapter 4.)
And here’s an example of how division is non-commutative:
For example, when you have five dog biscuits to divide between two dogs, each dog gets two biscuits and you have one biscuit left over. But when you switch the numbers and try to divide two biscuits among five dogs, you don’t have enough biscuits to go around, so each dog gets none and you have two left over.
Through the commutative property and inverse operations, every equation has four alternative forms that contain the same information expressed in slightly different ways. For example,
When the first number is missing in any problem, use the inverse to turn the problem around:
When the second number is missing in an addition or multiplication problem, use the commutative property and then the inverse:
When the second number is missing in a subtraction or division problem, just switch around the two values that are next to the equals sign (that is, the blank and the equals sign):
A.
Q. What’s the inverse equation to
A.
Q. Use inverse operations and the commutative property to find three alternative forms of the equation
A.
Now use the commutative property to change the order of this addition:
Finally, use inverse operations to change addition to subtraction:
Q. Fill in the blank:
A. 39. Use inverse operations to turn the problem from division to multiplication:
Now you can solve the problem by multiplying
Q. Solve this problem by filling in the blank:
A. 31. First, use the commutative property to reverse the addition:
Now use inverse operations to change the problem from addition to subtraction:
At this point, you can solve the problem by subtracting
Q. Fill in the blank:
A. 49. Switch around the last two numbers in the problem:
Now you can solve the problem by subtracting
1
(a)
(b)
(c)
(d)
2 Use the commutative property to write down an alternative form of each equation:
(a)
(b)